Consider the reaction: 2nh3 (aq) + ocl - (aq) →n2h4 (aq) + h2o (l) + cl - (aq) this three-step mechanism is proposed: nh3 (aq) + ocl - (aq) ⇌k1k2 nh2cl (aq) + oh - (aq) fast nh2ci (aq) + nh3 (aq) ⟶k3 n2h+5 (aq) + cl- - (aq) slow n2h+5 (aq) + oh - (aq) ⟶k4 n2h4 (aq) + h2o (l) fast part a does the mechanism sum to the reaction 2nh3 (aq) + ocl - (aq) →n2h4 (aq) + h2o (l) + cl - (aq) ?

Question

Sarah Ayers

Chemistry

25 June, 11:26

Consider the reaction: 2nh3 (aq) + ocl - (aq) →n2h4 (aq) + h2o (l) + cl - (aq) this three-step mechanism is proposed: nh3 (aq) + ocl - (aq) ⇌k1k2 nh2cl (aq) + oh - (aq) fast nh2ci (aq) + nh3 (aq) ⟶k3 n2h+5 (aq) + cl- - (aq) slow n2h+5 (aq) + oh - (aq) ⟶k4 n2h4 (aq) + h2o (l) fast part a does the mechanism sum to the reaction 2nh3 (aq) + ocl - (aq) →n2h4 (aq) + h2o (l) + cl - (aq) ?

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Answers (1)

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Case Leonard · Answer 1

Yes, the mechanism sums to the reaction.

You add the equations, cancelling species that occur on opposite sides of the arrows.

Eq1: NH3 (aq) + OCl^ (-) (aq) → NH2Cl (aq) + OH^ (-) (aq)

Eq2: NH2Cl (aq) + NH3 (aq) → N2H5^ (+) (aq) + Cl^ (-) (aq)

Eq3: N2H5^ (+) (aq) + OH^ (-) (aq) → N2H4 (aq) + H2O (l)

OA: 2NH3 (aq) + OCl^ (-) (aq) → N2H4 (aq) + H2O (l) + Cl^ (-) (aq)