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31 December, 23:53

The compound 1-iodododecane is a nonvolatile liquid with a density of 1.20g/ml. the density of mercury is 13.6g/ml. part a what do you predict for the height of a barometer column based on 1-iodododecane, when the atmospheric pressure is 751 torr?

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  1. 1 January, 00:08
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    As the atmospheric pressure is, P = dgh

    Here d is the density of the mercury,

    g is gravitation = 9.8 m/s²

    h is height of the column, P = 751 torr = (751 torr * 1 atm / 760 torr) (101325 Pa) (1 N/m² / 1 Pa) = 100125 N/m²

    Where, 1 N = 1 Kg / ms²

    Thus, P = 100125 Kg / m³. s²

    Therefore, height of the mercury column, when the atmospheric pressure is 751 torr,

    h = P / gd

    = (100125 kg / m³. s²) / (9.8 m/s²) (13.6 * 10³ kg / m³) = 0.751 m

    As, d₁h₁ = d₂h₂

    Here, d₁ is the density of the non-volatile liquid = 1.20 g/ml

    d₂ is the density of the mercury = 13.6 g/ml

    h₂ = 0.751 m

    Thus, putting the values we get,

    h₁ = d₂h₂ / d₁ = 13.6 g/ml * 0.751 m / 1.20 g/ml

    = 8.5 m
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