When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction caco3 (s) →cao (s) + co2 (g) what is the mass of calcium carbonate needed to produce 61.0 l of carbon dioxide at stp? express your answer with the appropriate units?

Question

Rayne Harmon

Chemistry

6 October, 22:03

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction caco3 (s) →cao (s) + co2 (g) what is the mass of calcium carbonate needed to produce 61.0 l of carbon dioxide at stp? express your answer with the appropriate units?

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Answers (1)

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Azul Abbott · Answer 1

Answer is: 227.3 grams of of calcium carbonate needed.

Chemical reaction: CaCO₃ → CaO + CO₂.

V (CO₂) = 61.0 L.

n (CO₂) = V (CO₂) : Vm.

n (CO₂) = 61 L : 22.4 L/mol.

n (CO₂) = 2.723 mol.

From chemical reaction: n (CO₂) : n (CaCO₃) = 1 : 1.

n (CaCO₃) = 2.273 mol.

m (CaCO₃) = n (CaCO₃) · M (CaCO₃).

m (CaCO₃) = 2.273 mol · 100 g/mol.

m (CaCO₃) = 227.3 g.