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25 January, 13:55

The atomic mass of europium is 151.9 amu. There are two naturally occuring isotopes on europium, eu-151 with a mass of 151.0 amu and eu153 with a mass of 153.0. The percent natural abundance of the eu151 should be

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  1. 25 January, 14:02
    0
    The natural abundance of eu-153 is 45.0 %

    The natural abundance of eu-151 is 55.0 %

    Explanation:

    Step 1: Data given

    The atomic mass of europium is 151.9 amu.

    eu-151 hass with a mass of 151.0 amu

    eu153 hass a mass of 153.0 amu

    Step 2: Calculate the percent natural abundance

    natural abundance eu-151 = X

    natural abundance eu-153 = 1-X

    151.9 = 151.0 * X + 153.0 * (1-X)

    151.9 = 151.0X + 153.0 - 153.0 X

    -1.1 = - 2.0 X

    X = 0.55 = 55 %

    The natural abundance of eu-153 is 45.0 %

    The natural abundance of eu-151 is 55.0 %
  2. 25 January, 14:11
    0
    55%

    Explanation:

    Let A represent isotope eu-151

    Let B represent isotope eu-153

    Let A% represent Abundance of isotope A (eu-151)

    Let B represent abundance of isotope B (eu-153)

    The abundance of isotope A (eu-151) can be obtained as follow:

    Step 1:

    Data obtained from the question include:

    Atomic mass of Europium = 151.9 amu

    Mass of isotope A (eu-151) = 151.0 amu

    Mass of isotope B (eu-153) = 153.0

    amu

    Abundance of isotope A (eu-151) = A%

    Abundance of B (eu-153) = B% = 100 - A%

    Step 2:

    Determination of the abundance of Abundance of isotope A (eu-151). This is illustrated below:

    Atomic mass = [ (Mass of A x A%) / 100] + [ (Mass of B x B%) / 100]

    151.9 = [ (151 x A%) / 100] + [ (153x B%) / 100]

    151.9 = [ (151 x A%) / 100] + [ (153x (100-A%)) / 100]

    151.9 = [151A%/100] + [15300 -

    153A%/100]

    151.9 = (151A% + 15300 - 153A%) / 100

    Cross multiply to express in linear form

    151.9 x100 = 151A% + 15300 - 153A%

    15190 = 151A% + 15300 - 153A%

    Collect like terms

    15190 - 15300 = 151A% - 153A%

    - 110 = - 2A%

    Divide both side by - 2

    A% = - 110 / - 2

    A% = 55%

    Therefore the abundance of eu-151 is 55%
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