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10 August, 17:18

Percentage compostion of carbon in CaCO3

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  1. 10 August, 17:42
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    Ca = 40.08 amu

    C = 12.01 amu

    O = 16 * 3 = 48 amu

    40.08 + 12.01 + 48 = 100.09 total amu

    12.01 / 100.09 = 0.1199 * 100 = about 12% C

    To find percent composition carbon you do

    12.01 amu divided by the total amu of compound times 100 ...

    amu is just the atomic mass number of the element/compound
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