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24 August, 16:23

Given the following balanced equation, calculate the theoretical yield of H2 in grams if you start with 25.3g Zn and have an excess of HCl. Zn (s) + 2HCl (aq) → ZnCl2 (aq) + H2

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  1. 24 August, 16:36
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    The theoretical yield of H₂ in grams is =

    calculation

    Zn (s) + 2HCl (aq) → ZnCl₂ (aq) + H₂

    Step 1: find the moles Zn

    moles = mass: molar mass

    from periodic table the molar mass of Zn = 65.4 g/mol

    moles is therefore = 25.3 g/65.4 g/mol=0.387 moles

    Step 2: use the mole ratio to determine the moles of H₂

    from given equation Zn:H₂ = 1:1 therefore the moles of H₂ is also = 0.387 moles

    Step 3: find theoretical mass of H₂

    mass = moles * molar mass

    from periodic table the molar mass of H₂ = 1 * 2 = 2 g/mol

    mass = 0.387 moles * 2 g/mol = 0.774 grams
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