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1 January, 17:57

What is the sum of the numbers of neutrons and electrons in the ion 208 Pb2+?

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  1. 1 January, 18:04
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    For ²⁰⁸Pb²⁺ cation, the sum of the number of neutrons and electrons = 206

    Explanation:

    Lead, chemical symbol Pb, is a chemical element which belongs to the group 14 of the periodic table. The atomic number of lead is 82 and it is a member of the p-block.

    The isotope of lead with the mass number 208, has 126 neutrons.

    Since, atomic number = number of protons = number of electrons for neutral atom

    Therefore, for ²⁰⁸Pb: number of electrons = 82

    So, for ²⁰⁸Pb²⁺ cation: number of electrons = 82 - 2 = 80

    Therefore, for ²⁰⁸Pb²⁺ cation, the sum of the number of neutrons and electrons = number of electrons + number of neutrons = 80 electrons + 126 neutrons = 206.
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