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14 December, 21:16

The permanent electric dipole moment of the water molecule 1H2O2 is 6.2 * 10-30 C m. What is the maximum possible torque on a water molecule in a 5.0 * 108 N/C electric field?

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  1. 14 December, 21:34
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    3.1 x 10⁻²¹ Nm

    Explanation:

    When placed in an external electric filed, an electric dipole experiences a torque. and this torque is represented mathematically with the equation:

    torque (τ) = dipole moment vector (P) x electric field vector (E)

    τ = P. E. sin θ

    where θ is the angle between the water molecule and the electric field, which in this case is 90° (because this is where the torque is maximum)

    τ = 6.2x10⁻³⁰Cm. 5.0x10⁸ N/C. sin90

    τ = 6.2x10⁻³⁰Cm. 5.0x10⁸ N/C. 1

    solve for τ

    τ = 3.1 x 10⁻²¹ Nm

    the maximum possible torque on the water molecule is therefore 3.1 x 10⁻²¹ Nm
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