How many milligrams of sodium sulfide are needed to completely react with 25.00 ml of a 0.0100 m aqueous solution of cadmium nitrate, to form a precipitate of cds (s) ?

Question

Olive Lamb

Chemistry

9 December, 06:36

How many milligrams of sodium sulfide are needed to completely react with 25.00 ml of a 0.0100 m aqueous solution of cadmium nitrate, to form a precipitate of cds (s) ?

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Makaila Jefferson · Answer 1

Na₂S (aq) + Cd (NO₃) ₂ (aq) = CdS (s) + 2NaNO₃ (aq)

v=25.00 mL

c=0.0100 mmol/mL

M (Na₂S) = 78.046 mg/mmol

n (Na₂S) = n{Cd (NO₃) ₂}=cv

m (Na₂S) = M (Na₂S) n (Na₂S) = M (Na₂S) cv

m (Na₂S) = 78.046*0.0100*25.00≈19.5 mg