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6 June, 09:02

Balance the following Equation:

___Zn + ___HCl - -> ___ZnCl2 + ___H2

50g of zinc are reacted with 50g of hydrogen chloride. Calculate the amount of excess reactant.

A - 4.2g

B - 5.1g

C - 1.4g

D - 2.3g

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Answers (1)
  1. 6 June, 09:06
    0
    The amount of excess is 5.16 grams. Option B is correct

    Explanation:

    Step 1: Data given

    Mass of Zinc (Zn) = 50.0 grams

    Mass of Hydrogen chloride (HCl) = 50.0 grams

    atomic mass Zn = 65.38 g/mol

    Molar mass HCl = 36.46 g/mol

    Step 2: The balanced equation

    Zn + 2HCl → ZnCl2 + H2

    step 3: Calculate moles

    Moles = mass / molar mass

    Moles Zn = 50.0 grams / 65.38 g/mol

    Moles Zn = 0.764 moles

    Moles HCl = 50.0 grams / 36.46 g/mol

    Moles HCl = 1.37 moles

    Step 4: Calculate limiting reactant

    For 1 mol n we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

    HCl is the limiting reactant. It will completely be consumed (1.37 moles)

    Zn is in excess. There will react 1.37/2 = 0.685 moles

    There will remain 0.764 - 0.685 = 0.079 moles

    Step 5: Calculate the remaining mass of zinc

    Mass = moles * molar mass

    Mass Zinc = 0.079 moles * 65.38 g/mol

    Mass Zinc = 5.16 grams

    The amount of excess is 5.16 grams. Option B is correct
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