Calculate the nuclear binding energy in mega-electronvolts (MeV) per nucleon for 136 Ba. 136 Ba has a nuclear mass of 135.905 amu. nuclear binding energy per nucleon:

8.194 Mev per nucleon

Explanation:

Mass of Barium = 135.905 amu

number of proton = 56, number of neutron = 80

Md = (Mp + Mn) - Mb Mp is the mass of proton, Mn is the mass of neutron, Mb is the mass of barium and Md is the mass defect

Mn = 1.00867 amu Mp = 1.00728 amu

Md = (56 (1.00728) + 80 (1.00867) = 137.1013 - 135.905 = 1.1963 amu

Md = 1.1963 * 1 : (6.02214 * 10 ²⁶ amu) = 1.9865 * 10 ⁻²⁷ kg

Energy = mc² = 1.9865 * 10 ⁻²⁷ kg * (2.99792 * 10 ⁸ m/s) ²

E = 1.78537 * 10⁻¹⁰ J

to convert to Mev

1.78537 * 10⁻¹⁰ * 6241457006000 = 1114.33 Mev

binding energy per nucleon = 1114.33 / 136 = 8.194 Mev per nucleon