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11 December, 20:24

Tori wants to increase the temperature of 500 grams of water from 20 c to 100 c if the specific heat of water is 4.18 j g c how much heat is needed

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  1. 11 December, 20:44
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    The heat needed is calculated as follows

    Q = mc delta T

    m = mass = 500g

    c = specific heat capacity = 4.18 j g c

    delta T = change in temperature 100 - 20 = 80 c

    Q is therefore = 500g x 4.18 j g c x 80 c = 167,200j or in Kj = 167200/1000=167.2 kj
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