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30 March, 17:23

Consider the following reaction 2X - -> Y + Z, when the concentration of X is doubled, the reaction rate increases by a factor of 4. What is the order of the reaction?

(A) zero order

(B) first-order

(C) second order

(D) third order

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  1. 30 March, 17:38
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    (C) second order

    Explanation:

    Let's consider the following reaction.

    2X - -> Y + Z

    The rate law is:

    r = k. [A]ˣ

    where,

    r is the rate of the reaction

    k is the rate constant

    x is the reaction order of A

    Let's assume x = 2. If the concentration of A is doubled, the new rate r₁ is:

    r₁ = k. [2A]² = 4. k. [A]² = 4. r

    The new rate r₁ is 4 times r when [A] is doubled. This happens when x = 2, that is, it is a second reaction order.
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