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1 January, 02:02

The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 x 102. What is the form of the equilibrium constant?

. [NH3]2

[N2][H2]3

. [NH3]_

[N2][H2]3

[NH3]2

[N2][H2]

[NH3]2

[N2][3H2]3

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  1. 1 January, 02:14
    0
    First option:

    [NH3]2 / [N2][H2]3

    Explanation:

    First of all we need to determine the reaction:

    N₂ (g) + 3H₂ (g) → 2NH₃ (g)

    1 mol of nitrogen can combine with 3 moles of hydrogen to produce 2 moles of ammonia.

    Remember that Kc has to involve Molar concentrations of products / reactants

    Concentration must be elevated to the stoichiometry coefficient

    Kc for the reaction is: [NH₃]² / [N₂]. [H₂]³
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