What is the rate law for the reaction that has the

following mechanism?

Step 1: NO (g) + NO (g) - N2O2 (g) (fast)

Step 2: N202 (g) + O2 (g) - 2NO2 (g) (slow)

rate = k[NO][N202]

rate = K[NO]2

rate = k[NO] [02]

Question

16 March, 06:57

+1

Answers (1)

Know the Answer?

Jamiya Duke · Answer 1

rate = k[NO] [02]

Explanation:

the N2O2 cancel because they are intermediates leaving 2NO + O2

What is the rate law for the reaction that has thefollowing mechanism?Step 1: NO (g) + NO (g) - N2O2 (g) (fast)Step 2: N202 (g) + O2 (g) - 2NO2 (g) (slow)rate = k[NO][N202]rate = K[NO]2rate = k[NO] [02]