Estimate the heat of neutralization of H3PO4 in kJ/mol given these dаta: Heat transferred = 2.2 x 102 J Moles of H3PO4 = 1.5 x 10-3 mol Moles of NaOH = 5.0 x 10-3 mol

Question

Makenna

Chemistry

17 September, 19:49

Estimate the heat of neutralization of H3PO4 in kJ/mol given these dаta: Heat transferred = 2.2 x 102 J Moles of H3PO4 = 1.5 x 10-3 mol Moles of NaOH = 5.0 x 10-3 mol

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Trinity Lyons · Answer 1

1.) write out the balance equation 3NaOh+H3PO4->Na3PO4+3H2O

2.) You are given everything needed to calculate q=heat transfer=2.2*10^2, H3PO4 moles = 1.5*10^-3, NaOH moles=5.0*10^-3

3.) equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first

4.) Now plug in variables DeltaH=2.2*10^2 (1.5*10^3) = 146.67kj/mole Notice we had to convert J to kj,

Nikolas Terrell · Answer 2

write out the balance equation

3NaOh+H3PO4->Na3PO4+3H2O

You are given everything needed to calculate

q=heat transfer=2.2*10^2,

H3PO4 moles = 1.5*10^-3,

NaOH moles=5.0*10^-3

equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first

Now plug in variables

DeltaH=2.2*10^2 (1.5*10^3) = 146.67kj/mole

Notice we had to convert J to kj,