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12 June, 03:56

What is the specific heat (J/g°C) of a metal object whose temperature increases by 3.0°C when 17.5 g of metal was heated with 38.5 J? a. 0.73 b. 0.15 c. 1.4 d. 4.18 e. none of the above

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  1. 12 June, 03:59
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    a. 0.73

    Explanation:

    Given data

    Added heat (Q) : 38.5 J Change in the temperature (ΔT) : 3.0°C Mass of the metal (m) : 17.5 g Specific heat of the metal (c) : ?

    We can determine the specific heat of the metal using the following expression.

    Q = c * m * ΔT

    c = Q / m * ΔT

    c = 38.5 J / 17.5 g * 3.0°C

    c = 0.73 J/g.°C
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