93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0 C. what would be the volume of this dry gas at STP

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Felipe

Chemistry

28 January, 04:36

93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0 C. what would be the volume of this dry gas at STP

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Catalina Rogers · Answer 1

Let us assume that the oxygen behaves as an ideal gas such that we can use the ideal gas equation to solve for the number of moles of O2.

PV = nRT; n = PV/RT

Substituting the known values,

n = (0.930 atm) (93/1000 L) / (0.0821 L. atm/mol. K) (10 + 273.15K)

n = 3.72 x 10^-3 mols

At STP, the volume of each mol of gas is equal to 22.4 L.

volume = (3.73 x 10^-3 mols) x (22.4 L/1 mol)

volume = 0.0833 L or 83.34 mL