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A tank contains 36.5 g of O₂ and 46.4 g of N₂ at a pressure of 3.64 atm. What is the pressure of O₂ in the tank (in atm) ?

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  1. 3 May, 03:05
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    Partial pressure O₂ = 1.49 atm

    Explanation:

    We can solve this, by the mole fraction concept.

    Mole fraction = Moles of gas / Total moles

    We can also define mole fraction as: Partial pressure of a gas / Total pressure

    Total moles = Moles of O₂ + Moles of N₂

    36.5 g. 1 mol / 32g + 46.4 g. 1mol / 28g = 2.79 moles

    1.14 moles O₂ + 1.65 moles N₂ = 2.79 moles

    Partial pressure O₂ / Total pressure = Moles of O₂ / Total moles

    Partial pressure O₂ = (Moles of O₂ / Total moles). Total pressure.

    We replace: (1.14 mol / 2.79 mol). 3.64 atm = 1.49 atm

    Partial pressure O₂ = 1.49 atm
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