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16 September, 13:51

A gas sample with a mass of 12.8 g exerts a pressure of 1.2 atm at 15°c and a volume of 3.94 l. what is the molar mass of the gas?

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  1. 16 September, 14:08
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    We can use the ideal gas law equation to find the number of moles in the gas

    PV = nRTwhere P - pressure - 1.2 atm x 101 325 Pa/atm = 121 590 Pa

    V - volume - 3.94 x 10⁻³ m³

    n - number of moles

    R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

    T - temperature - 15 °C + 273 = 288 K

    substituting the values in the equation

    121 590 Pa x 3.94 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 288 K

    n = 0.200 mol

    molar mass of gas is = mass / number of moles

    molar mass = 12.8 g / 0.200 mol = 64 g/mol

    molar mass of gas is 64 g/mol
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