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17 December, 03:24

A 4.10-mole sample of helium gas at 28°C takes up a volume of 3.28 L. Determine the pressure of helium in units of atm.

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  1. 17 December, 03:38
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    n = number of mole of sample of helium gas = 4.10

    T = temperature of the gas = 28 °C = 28 + 273 = 301 K

    V = Volume of helium gas = 3.28 L = 0.00328 m³

    P = pressure of the helium gas

    Using the equation

    P V = n R T

    P (0.00328) = (4.10) (8.314) (301)

    P = 3.13 x 10⁶ Pa

    P = (3.13 x 10⁶ Pa) (1 atm / (101325 Pa))

    P = (3.13 x 10⁶) atm / (101325)

    P = 30.89 atm
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