On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What is the atomic mass of chlorine for this location? The mass of 35Cl is 34.9700 amu. The mass of 37Cl is 36.9700 amu.

Question

Avah Perez

Chemistry

26 March, 02:51

On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What is the atomic mass of chlorine for this location? The mass of 35Cl is 34.9700 amu. The mass of 37Cl is 36.9700 amu.

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Answers (1)

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Sweety · Answer 1

36.693

Explanation:

From the question given, the following were obtained:

Let 35Cl be isotope A and 37Cl be isotope

For isotope A (35Cl),

Mass number = 34.9700

Abundance = 13.85 %

For isotope B (37Cl),

Mass number = 36.9700

Abundance = 86.15 %

Atomic mass =

[ (Mass of AxAbundance A) / 100] + [ (Mass of BxAbundance B) / 100]

[ (34.97x13.85) / 100] + [ (36.97x86.15) / 100]

= 36.693