What is the change in temperature in a 128g sample of titanium if it absorbs 2808J of heat energy at a temperature of 2°C? The specific heat of titanium is 0.523J / g °c.

Given:

128g sample of titanium

2808J of heat energy

specific heat of titanium is 0.523 J / g °C.

Required:

Change in temperature

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

Plugging in the values into the equation

H = mCpT

2808J = (128g) (0.523 J / g °C) T

T = 41.9 °C