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28 December, 08:54

Calculate the value of q (kj) in this exothermic reaction when 5.40 g of hydrogen peroxide decomposes at constant pressure?

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  1. 28 December, 09:23
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    Hydrogen peroxide decomposes to yield water and oxygen gas

    That is; H2O2 (l) = H2O (l) + O2 (g)

    The standard heat of formation; H2O2 (l) = - 187.6 kJ/mol; H2O (l) = - 285.8 kJ/mol

    1 mole of hydrogen peroxide contains 34 g

    Thus, 5.4 g contains 5.4/34 = 0.1588 moles

    The moles of water produced will also be equivalent to 0.1588 moles

    Heat = heat of formation of product - reactant

    Therefore; Heat = (0.1588 moles * - 285,8) - (0.1588 * - 187.6)

    = - 15.594 kJ
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