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22 November, 04:33

In standardizing a naoh solution a student found that 25.55cm of base neutralize exactly 21.35cm of 0.12M HCl find the molarity of the NaoH

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  1. 22 November, 04:47
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    O. 1M

    Explanation:

    First let's generate a balanced equation for the reaction

    NaOH + HCl - >NaCl + H2O

    From the equation,

    The ratio of the acid to base is 1:1.

    From the question, we obtained the following:

    Ma = Molarity of acid = 0.12M

    Va = volume of acid = 21.35cm3

    Vb = volume of base = 25.55cm3

    Mb = Molarity of base = ?

    We obtained nA (mole of acid) and nB (mole of base) to be 1

    The molarity of the base can be calculated for using:

    MaVa / MbVb = nA / nB

    0.12x21.35 / Mb x 25.55 = 1

    Cross multiply to express in linear form

    Mb x 25.55 = 0.12x21.35

    Divide both side by 25.55

    Mb = (0.12x21.35) / 25.55

    Mb = 0.1M

    The molarity of the base is 0.1M
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