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7 December, 07:36

What is the volume of 3.00 mole of ideal gas at 100.0 C and 2.00 kPa

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  1. 7 December, 07:38
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    The volume for the ideal gas is: 4647.5 Liters

    Explanation:

    Formula for the Ideal Gases Law must be applied to solve this question:

    P. V = n. R. T

    We convert the T° to K → 100°C + 273 = 373 K

    We convert pressure value from kPa to atm.

    2 kPa. 1atm/101.3 kPa = 0.0197 atm

    We replace data in the formula.

    V = (n. R. T) / P → (3 mol. 0.082. 373K) / 0.0197 atm =

    The volume for the ideal gas is: 4647.5 Liters
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