What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy

Question

Cameron Mayer

Chemistry

26 September, 04:47

What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy

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Answers (1)

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Serena · Answer 1

Moles = n = 3.91 mol

Pressure = P = 5.35 atm

Temperature = T = 323 K

Volume = V = ?

Formula used: Ideal Gas Equation is used,

P V = n R T

Solving for V,

V = n R T / P

Putting Values,

V = (3.91 mol * 0.0825 atm. L. mol⁻¹. K⁻¹ * 323 K) : 5.35 atm

V = 19.36 L