Calculate the percent yield if 52.9 g of ethanol reacts to produce 26.7 g of ether.

2CH3CH2OH (l) → CH3CH2OCH2CH3 (l) + H2O (l)

The % yield is 62.7 %

Explanation:

Step 1: the balanced equation

2CH3CH2OH (l) → CH3CH2OCH2CH3 (l) + H2O (l)

Step 2: Data given

mass of ethanol = 52.9 grams

molar mass of ethanol = 46.07 g/mol

mass of ether = 26.7 grams

Molar mass of ether = 74.12 g/mol

Step 3: Calculate moles of ethanol

Number of moles = Mass / molar mass

Moles of ethanol = 52.9 grams / 46.07 g/mol

Moles of ethanol = 1.15 moles

Step 4: Calculate moles of ether

For 2 moles of ethanol consumed, we have 1 mole of ether produced

For 1.15 moles of ethanol consumed, we have 1.15/2 = 0.575 moles of ether produced

Step 5: Calculate mass of ether

Mass = moles * Molar mass

Mass ether = 0.575 moles * 74.12 g/mol = 42.62 grams = theoretical yield

Step 6: Calculate % yield

% yield = (26.7 / 42.62) * 100 = 62.7%

The % yield is 62.7 %