During the time 0.325 mol of an ideal gas undergoes an isothermal compression at 22.0∘c, 352 j of work is done on it by the surroundings. part a if the final pressure is 1.76 atm, what was the initial pressure?

Question

Rosa Galvan

Chemistry

28 January, 11:45

During the time 0.325 mol of an ideal gas undergoes an isothermal compression at 22.0∘c, 352 j of work is done on it by the surroundings. part a if the final pressure is 1.76 atm, what was the initial pressure?

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Kevin Hines · Answer 1

According to the equation of the work done W:

When W = nRT㏑ (Pi/Pf) and we have:

W = 352 joule & n = 0.325 & T by kelvin = 22+273 = 295 K & Pf = 1.76

by the substitute:

352 = (0.325 x 8.314 x 295) ㏑ (Pi/Pf)

∴㏑ (Pi/Pf) = - 352 / (0.325 x 8.314 x 295)

㏑ (Pi/Pf) = - 0.44

Pi/Pf = 0.644

∴ Pi = 1.76 x 0.644 = 1.13 atm