In a sulphuric acid (h2so4) - sodium hydroxide (naoh) acid-base titration, 17.3 ml of 0.126 m naoh is needed to neutralize 25 ml of h2so4 of unknown concentration. find the morality of the h2so4 solution, given that the neutralization reaction that occurs is:

The balanced equation for the neutralisation reaction is as follows

2NaOH + H₂SO₄ - - - > Na₂SO₄ + 2H₂O

stoichiometry of NaOH to H₂SO₄ is 2:1

the number of moles of NaOH reacted - 0.126 mol/L x 0.0173 L = 0.00218 mol

if 2 mol of NaOH reacts with 1 mol of H₂SO₄

then 0.00218 mol of NaOH reacts with - 0.00218 / 2 = 0.00109 mol of H₂SO₄

molarity is the number of moles of solute in 1 L solution

therefore if 25 mL contains - 0.00109 mol

then 1000 mL contains - 0.00109 mol / 25 mL x 1000 mL = 0.0436 mol/L

therefore molarity of H₂SO₄ is 0.0436 M