Ask Question
23 May, 13:34

Will mark branliest. Calculating percent yield: For the reaction Cu + 2AgNO3 → Cu (NO3) 2 + 2 Ag, adding 127 grams of copper to lots of silver nitrate yields 410 grams of silver. What is the percent yield of silver?

I'm desperate.

+2
Answers (1)
  1. 23 May, 13:56
    0
    Percent yield = (Actual Yield / Theoretical Yield) x 100

    Given, Actual Yield of silver = 410 grams

    Given, mass of copper = 127 g

    Atomic mass of copper = 63.546 amu

    Formula: Moles = mass / atomic mass

    Moles of copper = 127 g / 63.546 amu = 1.998 mol

    Based on the given balanced chemical reaction, the molar ratio between Cu: Ag is 1:2

    So 1.998 mol of copper should yield (2 mol Ag / 1 mol Cu) x 1.998 mol of Cu = 3.996 mol

    Calculated mol of Ag = 3.996 mol

    Atomic mass of silver = 107.8682 amu

    Mass of silver = moles x atomic mass = 3.996 mol x 107.8682 amu = 431 g

    Based on the math, the theoretical yield = 431 g

    Percent yield of silver = (410g/431g) x 100 = 95. 13%

    The answer is 95. 13%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Will mark branliest. Calculating percent yield: For the reaction Cu + 2AgNO3 → Cu (NO3) 2 + 2 Ag, adding 127 grams of copper to lots of ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers