A balloon of helium was put in the freezer at - 23°C. Its volume at this temperature was 2.5 liters. It was removed from the freezer. Eventually, it reached a temperature of 177°C. What would its volume be at this temperature? (Neglect any force used to stretch the rubber balloon.) (1.) 45000 (2.) 0.22 (3.) 4.5 (4.) 1.4

Question

Brianna

Chemistry

18 July, 15:37

A balloon of helium was put in the freezer at - 23°C. Its volume at this temperature was 2.5 liters. It was removed from the freezer. Eventually, it reached a temperature of 177°C. What would its volume be at this temperature? (Neglect any force used to stretch the rubber balloon.) (1.) 45000 (2.) 0.22 (3.) 4.5 (4.) 1.4

+1

Answers (1)

Know the Answer?

Madelynn Vargas · Answer 1

4.5 L

Explanation:

We will use the combined gas law formula;

P₁V₁/T₁ = P₂V₂/T₂

Because the pressure remains the same, it cancels out and what remains is;

V₁/T₁ = V₂/T₂

Before evaluating remember to change the temperatures into Kelvin;

-23° = 250.15 K

177° = 450.15 K

We replace the variables with known values;

2.5 / 250.15 = V₂ / 450.15

V₂ = 2.5 / 250.15 * 450.15

V₂ = 4.4988 L

≅ 4.5 L