A barium hydroxide solution is prepared by dissolving 1.90 g of Ba (OH) 2 in water to make 71.1 mL of solution. What is the concentration of the solution in units of molarity?

The molarity of this solution is 0.156 M

Explanation:

Step 1: Data given

Mass of Ba (OH) 2 = 1.90 grams

Molar mass Ba (OH) 2 = 171.34 g/mol

Volume of the solution = 71.1 mL = 0.0711 L

Step 2: Calculate moles Ba (OH) 2

Moles Ba (OH) 2 = mass Ba (OH) 2 / molar mass Ba (OH) 2

Moles Ba (OH) 2 = 1.90 grams / 171.34 g/mol

Moles Ba (OH) 2 = 0.0111 moles

Step 3: Calculate molarity

Molarity solutin = moles Ba (OH) 2 / volume solution

Molarity solution = 0.0111 moles / 0.0711 L

Molarity solution = 0.156 M

The molarity of this solution is 0.156 M