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13 August, 12:59

43. Calculate the root mean square velocity (r. m. s.) of 1 mole of CO2 at 270C (mm = 44gmol-1

)

A. 4.12 x 102m/s

B. 12 x 102m/s

C. 5.2 x 102m/s

D. 1.2 x 102m/s

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Answers (1)
  1. 13 August, 13:03
    0
    5.2 x 102m/s

    Explanation:

    v (rms) = square root of 3RT divided molar mass in kg

    R = 8.3J/molK T = 543 kelvin

    3 (8.3) (543) /.044=307289 m^2/s^2

    square root 5.2X10^2 m/2
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