43. Calculate the root mean square velocity (r. m. s.) of 1 mole of CO2 at 270C (mm = 44gmol-1

)

A. 4.12 x 102m/s

B. 12 x 102m/s

C. 5.2 x 102m/s

D. 1.2 x 102m/s

Question

Conor Bolton

Chemistry

13 August, 12:59

43. Calculate the root mean square velocity (r. m. s.) of 1 mole of CO2 at 270C (mm = 44gmol-1

)

A. 4.12 x 102m/s

B. 12 x 102m/s

C. 5.2 x 102m/s

D. 1.2 x 102m/s

+3

Answers (1)

Know the Answer?

Lorelai Ross · Answer 1

5.2 x 102m/s

Explanation:

v (rms) = square root of 3RT divided molar mass in kg

R = 8.3J/molK T = 543 kelvin

3 (8.3) (543) /.044=307289 m^2/s^2

square root 5.2X10^2 m/2

43. Calculate the root mean square velocity (r. m. s.) of 1 mole of CO2 at 270C (mm = 44gmol-1)A. 4.12 x 102m/sB. 12 x 102m/sC. 5.2 x 102m/sD. 1.2 x 102m/s

43. Calculate the root mean square velocity (r. m. s.) of 1 mole of CO2 at 270C (mm = 44gmol-1

)

A. 4.12 x 102m/s

B. 12 x 102m/s

C. 5.2 x 102m/s

D. 1.2 x 102m/s