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18 April, 19:08

How many moles of libr are contained in 347 g of water in a 0.175 m libr solution?

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  1. 18 April, 19:26
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    Molarity = number of moles of solute/Kg of solvent

    Molarity is given in the problem as 0.175 m

    Mass of solvent = 347 gm = 0.347 Kg

    Therefore,

    0.175 = number of moles of LiBr / 0.347

    number of moles of LiBr = 0.175 x 0.347 = 0.060725 moles
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