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15 September, 10:05

Calculate whether a precipitate will form (and why) if 0.35 l of 0.0044 m ca (no3) 2 and 0.17 l of 0.00039 m naoh are mixed at 25◦c. ksp for ca (oh) 2 is equal to 5.5 * 10-6.

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  1. 15 September, 10:27
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    Chemical reaction: Ca (NO₃) ₂ + 2NaOH → Ca (OH) ₂ + 2NaNO₃.

    c₁ (Ca (NO₃) ₂) · V₁ (Ca (NO₃) ₂) = c₂ (Ca (NO₃) ₂) · V₂ (Ca (NO₃) ₂).

    0.0044 M · 0.35 L = c₂ (Ca (NO₃) ₂) · (0.35 L + 0.17 L).

    [Ca²⁺] = c₂ (Ca (NO₃) ₂) = 0.00296 M.

    c₁ (NaOH) · V₁ (NaOH) = c₂ (NaOH) · V₂ (NaOH).

    0.00039 M · 0.17 L = c₂ (NaOH) · (0.35 L + 0.17 L)

    [OH⁻] = c₂ (NaOH) = 0.0001275 M.

    Q (Ca (OH) ₂) = [Ca²⁺] · [OH⁻]².

    Q = 0.00296 M · (0.0001275 M) ² = 4.9·10⁻¹¹.

    Ca (OH) ₂ does not precipitate because Q < Ksp.
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