What will the pressure of a gas be that contains 4.00 moles at a temperature of 88˚C in a container with a volume of 5.00 Liters?

P = 23.78 atm

Explanation:

Given dа ta:

Number of moles of gas = 4.00 mol

Temperature = 88°C

Volume of gas = 5 L

Pressure of gas = ?

Solution;

The given problem will be solve by using general gas equation,

PV = nRT

P = Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm. L / mol. K

T = temperature in kelvin

Now we will convert the temperature.

88 + 273 = 362 K

P = nRT/V

P = 4 mol * 0.0821 atm. L / mol. K * 362 K / 5 L

P = 118.88 atm / 5

P = 23.78 atm