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16 June, 16:37

The Ka of a monoprotic weak acid is 6.07 * 10-3. What is the percent ionization of a 0.179 M solution of this acid?

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  1. 16 June, 17:04
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    What you need to do my friend is write the chemical equation of dissociation of your acid AH with water, with initial concentration co, then consider that a fraction α reacts with water. Concentration and Ka are big enough so that you can consider that

    1-α≈1

    Then write expression of Ka, then solve for α. You should find about 18.4% I hope this works really good for you
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