Calculate the enthalpy of the reaction

2NO (g) + O2 (g) →2NO2 (g)

given the following reactions and enthalpies of formation:

12N2 (g) + O2 (g) →NO2 (g), ΔfH∘A=33.2 kJ mol-1

12N2 (g) + 12O2 (g) →NO (g), ΔfH∘B=90.2 kJ mol-1

Question

Rambler

Chemistry

21 December, 04:31

Calculate the enthalpy of the reaction

2NO (g) + O2 (g) →2NO2 (g)

given the following reactions and enthalpies of formation:

12N2 (g) + O2 (g) →NO2 (g), ΔfH∘A=33.2 kJ mol-1

12N2 (g) + 12O2 (g) →NO (g), ΔfH∘B=90.2 kJ mol-1

+3

Answers (1)

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Johanna Castaneda · Answer 1

We write the enthalpy change equation:

2ΔH_formation (NO) = ΔH_reaction + 2ΔH_formation (NO₂)

2 (90.2) = ΔHr + 2 (33.2)

ΔHr = 114 kJ/mol

The reaction releases 114 kJ/mol

Calculate the enthalpy of the reaction2NO (g) + O2 (g) →2NO2 (g)given the following reactions and enthalpies of formation:12N2 (g) + O2 (g) →NO2 (g), ΔfH∘A=33.2 kJ mol-112N2 (g) + 12O2 (g) →NO (g), ΔfH∘B=90.2 kJ mol-1

Calculate the enthalpy of the reaction

2NO (g) + O2 (g) →2NO2 (g)

given the following reactions and enthalpies of formation:

12N2 (g) + O2 (g) →NO2 (g), ΔfH∘A=33.2 kJ mol-1

12N2 (g) + 12O2 (g) →NO (g), ΔfH∘B=90.2 kJ mol-1