Suppose that, in a given reaction, the enthalpy (H) increases by 10 units, and the disorder (TS) increases by 12 units. By how many units did the Gibbs free energy change? When I did the calculation it came out to 2 units but the answer is - 2 units. Why is that? Also, is T (delta) S treated as one single unit or separate?

Question

Trevin Phelps

Chemistry

4 December, 00:49

Suppose that, in a given reaction, the enthalpy (H) increases by 10 units, and the disorder (TS) increases by 12 units. By how many units did the Gibbs free energy change? When I did the calculation it came out to 2 units but the answer is - 2 units. Why is that? Also, is T (delta) S treated as one single unit or separate?

+2

Answers (1)

Know the Answer?

Ingrid Acosta · Answer 1

-2

Explanation:

Gibbs free energy is defined by enthalpy of the system minus the product of the temperature and entropy and represented by the formula below:

G = H - TS where G = Gibbs free energy, H = enthalpy and T = temperature and S = entropy

change in entropy is defined by the formula below

ΔG = ΔH - Δ (TS) if the temperature is not constant, but if the temperature is constant then

ΔG = ΔH - TΔS

in according to the question (TS) is treated together.

to the solution

increase in H = 10 units, increase in the product of temperature and entropy = 12 units

ΔG = 10 - 12 = - 2