Calculate the amount of heat needed to boil 183. g of ethanol (CH3CH2OH), beginning from a temperature of 33.9°C. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.

19,700 Joules

Explanation:

Quantity of heat (Q) = mc (T2-T1)

m (mass of ethanol) = 183g

c (specific heat capacity of ethanol) = 2.44J/g°C

T2 (boiling temperature of ethanol) = 78°C

T1 (initial temperature of ethanol) = 33.9°C

Q = 183*2.44 (78 - 33.9) = 183*2.44*44.1 = 19691.532 = 19,700 Joules (to three significant digits)