How many formula units of silver fluoride, AgF, are equal to 42.15 g of this substance?

2.05 * 10²³ formula units

Explanation:

Given dа ta:

Mass of AgF = 43.15 g

Number of formula units = ?

Solution:

Number of moles of AgF:

Number of moles = mass / molar mass

Number of moles = 43.15 g / 126.87 g/mol

Number of moles = 0.34 mol

Now Number of formula units will be determine by using Avogadro number.

It is the number of atoms, ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 * 10²³ is called Avogadro number

1 mole = 6.022 * 10²³ formula units

0.34 mol * 6.022 * 10²³ formula units

2.05 * 10²³ formula units