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31 December, 10:21

How many atoms of oxygen are in 4.6 grams of copper sulfate

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  1. 31 December, 10:33
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    m (CuSO4*5H2O) = 424.0 g

    M (CuSO4*5H2O) = 249.68 g/mol

    n=m/M

    n (CuSO4*5H2O) = 1.7 mol

    There are 9 atoms of oxygen in each formula unit of CuSO4*5H2O. Therefore,

    n (O) = 8.5 mol

    M (O) = 16 g/mol

    m=M*n

    m (O) = 135.6 g
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