What is the oh - given the value of h30 + = (9.61x10^-2) M?

OH⁻ = 1.05*10⁻¹³ M

Explanation:

Given data;

H₃O⁺ = 9.61*10⁻² M

OH⁻ = ?

Solution:

First of all we will calculate the pH.

pH = - log [H⁺]

pH = - log [H₃O⁺]

Because pH is also the hydronium ion concentration.

pH = - log [ 9.61*10⁻²]

pH = 1.02

It is known that,

pH + pOH = 14

1.02 + pOH = 14

pOH = 14 - 1.02

pOH = 12.98

Concentration of OH⁻.

pOH = - log [OH⁻]

12.98 = - log [OH⁻]

OH⁻ = 10∧-12.98

OH⁻ = 1.05*10⁻¹³ M