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8 July, 23:36

What is the oh - given the value of h30 + = (9.61x10^-2) M?

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  1. 8 July, 23:46
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    OH⁻ = 1.05*10⁻¹³ M

    Explanation:

    Given data;

    H₃O⁺ = 9.61*10⁻² M

    OH⁻ = ?

    Solution:

    First of all we will calculate the pH.

    pH = - log [H⁺]

    pH = - log [H₃O⁺]

    Because pH is also the hydronium ion concentration.

    pH = - log [ 9.61*10⁻²]

    pH = 1.02

    It is known that,

    pH + pOH = 14

    1.02 + pOH = 14

    pOH = 14 - 1.02

    pOH = 12.98

    Concentration of OH⁻.

    pOH = - log [OH⁻]

    12.98 = - log [OH⁻]

    OH⁻ = 10∧-12.98

    OH⁻ = 1.05*10⁻¹³ M
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