Ask Question
30 April, 15:02

Under certain conditions, the substances zinc oxide and water combine to form zinc hydroxide. If 30.1 grams of zinc oxide and 6.7 grams of water combine to form zinc hydroxide, how many grams of zinc hydroxide must form

+2
Answers (1)
  1. 30 April, 15:30
    0
    36.8g of Zinc hydroxide

    Explanation:

    Based on the reaction:

    ZnO + H₂O → Zn (OH) ₂

    Where 1 mole of zinc oxide reacts with 1 mole of water to produce 1 mole of zinc hydroxide.

    Moles of 30.1g of ZnO (FW = 81.38g/mol) are:

    30.1g ZnO ₓ (1mol / 81.38g) = 0.370 moles of ZnO

    And moles of 6.7g of H₂O (FW = 18.01g/mol) are:

    6.7g H₂O ₓ (1mol / 18.01g) = 0.372 moles of H₂O

    As 1 mole of ZnO reacts per mole of H₂O, limiting reactant is ZnO because has a less number of moles than water.

    Thus, moles of Zn (OH) ₂ produced are 0.370 moles.

    As Molar mass of Zinc hydroxide is 99.424 g/mol, there are formed:

    0.370 moles Zn (OH) ₂ ₓ (99.424g / mol) =

    36.8g of Zinc hydroxide
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Under certain conditions, the substances zinc oxide and water combine to form zinc hydroxide. If 30.1 grams of zinc oxide and 6.7 grams of ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers