What is the molarity of a solution prepared from 100g of AlF3 dissolved in 1200 mL of water?

Given value is

Solute=100g of AlF3

Solution = 1200ml

Formula is;

Molarity = mole of solution / solution in liter

We have to find moles first.

For this purpose apply formula

No. of mole=mass in g / molar mass

Mass = 100g

Molar mass = 83.9767g/mol

No of mole = 100/83.9767

= 1.191mol

Now convert solution into liter

1200ml = 1200/1000 = 1.2L

Now put these values in molarity formula

Molarity = no. of mole / solution in liter

= 1.191mole of AlF3/1.2L of water

= 0.9925M of AlF3