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11 July, 20:51

What is the pH of 1.5x10^-3M of NaOH?

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  1. 11 July, 21:07
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    - log (1.5 x 10^-3) = pOH = 2.824

    14 - 2.824 = pH = 11.176

    10 ^ (-11.176) = [H3O+] = 6.668 x 10^-12
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