How many moles of co2 can be produced by the complete reaction of 1.53 g of lithium carbonatewith excess hydrochloric acid (balanced chemical reaction is given below) ? li2co3 (s) + 2hcl (aq) - - > 2licl (aq) + h2o (l) + co2 (g?

Question

Quintin Cabrera

Chemistry

14 January, 23:40

How many moles of co2 can be produced by the complete reaction of 1.53 g of lithium carbonatewith excess hydrochloric acid (balanced chemical reaction is given below) ? li2co3 (s) + 2hcl (aq) - - > 2licl (aq) + h2o (l) + co2 (g?

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Burnett · Answer 1

Moles of Li2CO3 = 1.53/73.891 = 0.0207 mole

Since HCl is in excess, amount of CO2 will depend on the limiting reagent which is Li2CO3.

∴Moles of CO2 = Moles of Li2CO3 = 0.0207.