What volume of 2.5% (m/v) koh can be prepared from 125 ml of a 5.0% (m/v) koh solution?

the volume of 2.5% m/v koh which can prepared from 125 ml of a 5% koh solution is calculated using the following formula

m1v1 = m2 v2

M1 = 5/100 = 0.05

v1 = 125

m2=2.5/100=0.025

V2=?

v2 = m1v1/m2

=0.05 x125 / 0.025=250 ml