A solution contains 44.0 ml of benzene in 125 ml of hexane what are the mass % and the volume % of the solution

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Mauricio Reid

Chemistry

15 March, 23:38

A solution contains 44.0 ml of benzene in 125 ml of hexane what are the mass % and the volume % of the solution

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Dale · Answer 1

V (benzene - C₆H₆) = 44,0 ml.

V (hexane - C₆H₁₄) = 125 ml.

V (solution) = 44 ml + 125 ml = 169 ml.

volume/volume percent (v/v%) = (volume of solute) / (volume of solution) · 100%.

v/v% = 44 ml : 169 ml · 100%.

v/v% = 26%.

m (C₆H₆) = d (C₆H₆) · V (C₆H₆).

m (C₆H₆) = 0,87 g/ml · 44 ml = 38,28 g.

m (C₆H₁₄) = 0,66 g/ml · 125 ml = 82,5 g.

m (solution) = 38,28 g + 82,5 g = 120,78 g.

mass% = 38,28 g : 120,78 g · 100% = 31,7%.